Base | Representation |
---|---|
bin | 1001001011010010101… |
… | …11101100010111111001 |
3 | 1010010211211101110202211 |
4 | 10211221113230113321 |
5 | 20131213402300403 |
6 | 400502542255121 |
7 | 31531303306045 |
oct | 4455127542771 |
9 | 1103754343684 |
10 | 315300431353 |
11 | 111799967896 |
12 | 511355874a1 |
13 | 2396a996b9b |
14 | 1139120d025 |
15 | 8305a6a06d |
hex | 49695ec5f9 |
315300431353 has 8 divisors (see below), whose sum is σ = 324954106400. Its totient is φ = 305752261248.
The previous prime is 315300431311. The next prime is 315300431359. The reversal of 315300431353 is 353134003513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 315300431353 - 217 = 315300300281 is a prime.
It is a super-2 number, since 2×3153004313532 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (315300431359) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26370168 + ... + 26382121.
It is an arithmetic number, because the mean of its divisors is an integer number (40619263300).
Almost surely, 2315300431353 is an apocalyptic number.
It is an amenable number.
315300431353 is a deficient number, since it is larger than the sum of its proper divisors (9653675047).
315300431353 is a wasteful number, since it uses less digits than its factorization.
315300431353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52752471.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 315300431353 its reverse (353134003513), we get a palindrome (668434434866).
The spelling of 315300431353 in words is "three hundred fifteen billion, three hundred million, four hundred thirty-one thousand, three hundred fifty-three".
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