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31531344313481 is a prime number
BaseRepresentation
bin1110010101101011101101…
…00100111011110010001001
311010122100220121011222222222
413022311312210323302021
513113102143121012411
6151021144414223425
76433031051316005
oct712656644736211
9133570817158888
1031531344313481
11a057405932051
123652b9b4b4b75
13147951559c8bc
147b01a77d9705
1539a308ce24db
hex1cad7693bc89

31531344313481 has 2 divisors, whose sum is σ = 31531344313482. Its totient is φ = 31531344313480.

The previous prime is 31531344313477. The next prime is 31531344313519. The reversal of 31531344313481 is 18431344313513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16826535264256 + 14704809049225 = 4102016^2 + 3834685^2 .

It is a cyclic number.

It is not a de Polignac number, because 31531344313481 - 22 = 31531344313477 is a prime.

It is a super-3 number, since 3×315313443134813 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (31531344313981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15765672156740 + 15765672156741.

It is an arithmetic number, because the mean of its divisors is an integer number (15765672156741).

Almost surely, 231531344313481 is an apocalyptic number.

It is an amenable number.

31531344313481 is a deficient number, since it is larger than the sum of its proper divisors (1).

31531344313481 is an equidigital number, since it uses as much as digits as its factorization.

31531344313481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 622080, while the sum is 44.

Adding to 31531344313481 its reverse (18431344313513), we get a palindrome (49962688626994).

The spelling of 31531344313481 in words is "thirty-one trillion, five hundred thirty-one billion, three hundred forty-four million, three hundred thirteen thousand, four hundred eighty-one".