Base | Representation |
---|---|
bin | 101101111000101011111… |
… | …001010000000011000011 |
3 | 102011110001212220222011121 |
4 | 231320223321100003003 |
5 | 403130320030022431 |
6 | 10412325104253111 |
7 | 443546200236046 |
oct | 55705371200303 |
9 | 12143055828147 |
10 | 3153242423491 |
11 | 1006312163666 |
12 | 42b152611197 |
13 | 19b470a82834 |
14 | ac891156c5d |
15 | 57052d01611 |
hex | 2de2be500c3 |
3153242423491 has 2 divisors, whose sum is σ = 3153242423492. Its totient is φ = 3153242423490.
The previous prime is 3153242423447. The next prime is 3153242423537. The reversal of 3153242423491 is 1943242423513.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3153242423491 - 225 = 3153208869059 is a prime.
It is not a weakly prime, because it can be changed into another prime (3153242423791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1576621211745 + 1576621211746.
It is an arithmetic number, because the mean of its divisors is an integer number (1576621211746).
Almost surely, 23153242423491 is an apocalyptic number.
3153242423491 is a deficient number, since it is larger than the sum of its proper divisors (1).
3153242423491 is an equidigital number, since it uses as much as digits as its factorization.
3153242423491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 622080, while the sum is 43.
The spelling of 3153242423491 in words is "three trillion, one hundred fifty-three billion, two hundred forty-two million, four hundred twenty-three thousand, four hundred ninety-one".
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