Base | Representation |
---|---|
bin | 1001001011011000101… |
… | …01101101100000001011 |
3 | 1010010222022010011222012 |
4 | 10211230111231200023 |
5 | 20131314130241324 |
6 | 400511522050135 |
7 | 31532446561355 |
oct | 4455425554013 |
9 | 1103868104865 |
10 | 315350243339 |
11 | 111814a9a31a |
12 | 5114a1a994b |
13 | 239780b7831 |
14 | 11397a980d5 |
15 | 830a10920e |
hex | 496c56d80b |
315350243339 has 2 divisors, whose sum is σ = 315350243340. Its totient is φ = 315350243338.
The previous prime is 315350243317. The next prime is 315350243443. The reversal of 315350243339 is 933342053513.
It is a weak prime.
It is an emirp because it is prime and its reverse (933342053513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 315350243339 - 220 = 315349194763 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 315350243296 and 315350243305.
It is not a weakly prime, because it can be changed into another prime (315350243939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157675121669 + 157675121670.
It is an arithmetic number, because the mean of its divisors is an integer number (157675121670).
Almost surely, 2315350243339 is an apocalyptic number.
315350243339 is a deficient number, since it is larger than the sum of its proper divisors (1).
315350243339 is an equidigital number, since it uses as much as digits as its factorization.
315350243339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 41.
The spelling of 315350243339 in words is "three hundred fifteen billion, three hundred fifty million, two hundred forty-three thousand, three hundred thirty-nine".
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