Base | Representation |
---|---|
bin | 11101010111111011… |
… | …101110000101000001 |
3 | 10000102002011020201101 |
4 | 131113323232011001 |
5 | 1004043222402342 |
6 | 22253404334401 |
7 | 2164406644222 |
oct | 352773560501 |
9 | 100362136641 |
10 | 31540044097 |
11 | 12415594a51 |
12 | 6142844401 |
13 | 2c88467cb3 |
14 | 1752bb3249 |
15 | c48e333b7 |
hex | 757eee141 |
31540044097 has 2 divisors, whose sum is σ = 31540044098. Its totient is φ = 31540044096.
The previous prime is 31540044079. The next prime is 31540044131. The reversal of 31540044097 is 79044004513.
Together with previous prime (31540044079) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31323336256 + 216707841 = 176984^2 + 14721^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31540044097 is a prime.
It is not a weakly prime, because it can be changed into another prime (31540044017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770022048 + 15770022049.
It is an arithmetic number, because the mean of its divisors is an integer number (15770022049).
Almost surely, 231540044097 is an apocalyptic number.
It is an amenable number.
31540044097 is a deficient number, since it is larger than the sum of its proper divisors (1).
31540044097 is an equidigital number, since it uses as much as digits as its factorization.
31540044097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
The spelling of 31540044097 in words is "thirty-one billion, five hundred forty million, forty-four thousand, ninety-seven".
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