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315401241 = 3711480757
BaseRepresentation
bin10010110011001…
…010010000011001
3210222111001011110
4102303022100121
51121220314431
651144050533
710546603101
oct2263122031
9728431143
10315401241
11152043691
1289763a49
1350460c6c
142dc62201
151ca52346
hex12cca419

315401241 has 8 divisors (see below), whose sum is σ = 426458304. Its totient is φ = 207305840.

The previous prime is 315401239. The next prime is 315401249. The reversal of 315401241 is 142104513.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 315401241 - 21 = 315401239 is a prime.

It is a super-4 number, since 4×3154012414 (a number of 35 digits) contains 4444 as substring.

It is not an unprimeable number, because it can be changed into a prime (315401249) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 740166 + ... + 740591.

It is an arithmetic number, because the mean of its divisors is an integer number (53307288).

Almost surely, 2315401241 is an apocalyptic number.

It is an amenable number.

315401241 is a deficient number, since it is larger than the sum of its proper divisors (111057063).

315401241 is a wasteful number, since it uses less digits than its factorization.

315401241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1480831.

The product of its (nonzero) digits is 480, while the sum is 21.

The square root of 315401241 is about 17759.5394365958. The cubic root of 315401241 is about 680.6979864492.

Adding to 315401241 its reverse (142104513), we get a palindrome (457505754).

The spelling of 315401241 in words is "three hundred fifteen million, four hundred one thousand, two hundred forty-one".

Divisors: 1 3 71 213 1480757 4442271 105133747 315401241