Base | Representation |
---|---|
bin | 1110010101111100010000… |
… | …11110000111110000101011 |
3 | 11010200012212011112211101222 |
4 | 13022332020132013300223 |
5 | 13113223400004431021 |
6 | 151025214512532255 |
7 | 6433464261253145 |
oct | 712761036076053 |
9 | 133605764484358 |
10 | 31540234452011 |
11 | a06015810677a |
12 | 365486085108b |
13 | 147a3013658bc |
14 | 7b07ac3b3c95 |
15 | 39a67951c6ab |
hex | 1caf88787c2b |
31540234452011 has 2 divisors, whose sum is σ = 31540234452012. Its totient is φ = 31540234452010.
The previous prime is 31540234451987. The next prime is 31540234452019. The reversal of 31540234452011 is 11025443204513.
It is a strong prime.
It is an emirp because it is prime and its reverse (11025443204513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31540234452011 - 210 = 31540234450987 is a prime.
It is not a weakly prime, because it can be changed into another prime (31540234452019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770117226005 + 15770117226006.
It is an arithmetic number, because the mean of its divisors is an integer number (15770117226006).
Almost surely, 231540234452011 is an apocalyptic number.
31540234452011 is a deficient number, since it is larger than the sum of its proper divisors (1).
31540234452011 is an equidigital number, since it uses as much as digits as its factorization.
31540234452011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 31540234452011 its reverse (11025443204513), we get a palindrome (42565677656524).
The spelling of 31540234452011 in words is "thirty-one trillion, five hundred forty billion, two hundred thirty-four million, four hundred fifty-two thousand, eleven".
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