Base | Representation |
---|---|
bin | 1110010110000100000100… |
… | …01100011010110010001011 |
3 | 11010200121200011010210000211 |
4 | 13023002002030122302023 |
5 | 13113310440033142324 |
6 | 151031150335541551 |
7 | 6434003143643062 |
oct | 713020214326213 |
9 | 133617604123024 |
10 | 31544424115339 |
11 | a061a08062853 |
12 | 365562b98a8b7 |
13 | 147a81b362725 |
14 | 7b0a889b91d9 |
15 | 39a822259294 |
hex | 1cb08231ac8b |
31544424115339 has 2 divisors, whose sum is σ = 31544424115340. Its totient is φ = 31544424115338.
The previous prime is 31544424115319. The next prime is 31544424115397. The reversal of 31544424115339 is 93351142444513.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31544424115339 - 215 = 31544424082571 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31544424115292 and 31544424115301.
It is not a weakly prime, because it can be changed into another prime (31544424115319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15772212057669 + 15772212057670.
It is an arithmetic number, because the mean of its divisors is an integer number (15772212057670).
Almost surely, 231544424115339 is an apocalyptic number.
31544424115339 is a deficient number, since it is larger than the sum of its proper divisors (1).
31544424115339 is an equidigital number, since it uses as much as digits as its factorization.
31544424115339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3110400, while the sum is 49.
The spelling of 31544424115339 in words is "thirty-one trillion, five hundred forty-four billion, four hundred twenty-four million, one hundred fifteen thousand, three hundred thirty-nine".
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