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315445234515353 is a prime number
BaseRepresentation
bin100011110111001010101000…
…1001001100011110110011001
31112100220021021202120210201222
41013232111101021203312121
5312321223320013442403
63034521312402421425
7123305110655626205
oct10756252111436631
91470807252523658
10315445234515353
1191568633275288
122b467496961875
1310702486624337
1457c78b8d47b05
1526706c3bd1338
hex11ee551263d99

315445234515353 has 2 divisors, whose sum is σ = 315445234515354. Its totient is φ = 315445234515352.

The previous prime is 315445234515293. The next prime is 315445234515419. The reversal of 315445234515353 is 353515432544513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 251993622730249 + 63451611785104 = 15874307^2 + 7965652^2 .

It is a cyclic number.

It is not a de Polignac number, because 315445234515353 - 26 = 315445234515289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 315445234515295 and 315445234515304.

It is not a weakly prime, because it can be changed into another prime (315445134515353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157722617257676 + 157722617257677.

It is an arithmetic number, because the mean of its divisors is an integer number (157722617257677).

Almost surely, 2315445234515353 is an apocalyptic number.

It is an amenable number.

315445234515353 is a deficient number, since it is larger than the sum of its proper divisors (1).

315445234515353 is an equidigital number, since it uses as much as digits as its factorization.

315445234515353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32400000, while the sum is 53.

The spelling of 315445234515353 in words is "three hundred fifteen trillion, four hundred forty-five billion, two hundred thirty-four million, five hundred fifteen thousand, three hundred fifty-three".