31550142433 has 4 divisors (see below), whose sum is σ = 31632519168. Its totient is φ = 31467765700.

The previous prime is 31550142419. The next prime is 31550142439. The reversal of 31550142433 is 33424105513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31550142433 is a prime.

It is a super-2 number, since 2×31550142433² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31550142395 and 31550142404.

It is not an unprimeable number, because it can be changed into a prime (31550142439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41187793 + ... + 41188558.

It is an arithmetic number, because the mean of its divisors is an integer number (7908129792).

Almost surely, 2^31550142433 is an apocalyptic number.

It is an amenable number.

31550142433 is a deficient number, since it is larger than the sum of its proper divisors (82376735).

31550142433 is an equidigital number, since it uses as much as digits as its factorization.

31550142433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82376734.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 31550142433 its reverse (33424105513), we get a palindrome (64974247946).

The spelling of 31550142433 in words is "thirty-one billion, five hundred fifty million, one hundred forty-two thousand, four hundred thirty-three".