Base | Representation |
---|---|
bin | 1110010110010000101100… |
… | …11001001010001000000011 |
3 | 11010201021011202102021200211 |
4 | 13023020112121022020003 |
5 | 13113413332043401433 |
6 | 151034231303254551 |
7 | 6434333166225553 |
oct | 713102631121003 |
9 | 133637152367624 |
10 | 31551205450243 |
11 | a064877a36066 |
12 | 3656a02a4a457 |
13 | 147b35c27772b |
14 | 7b112d495163 |
15 | 39aabc77d8cd |
hex | 1cb21664a203 |
31551205450243 has 16 divisors (see below), whose sum is σ = 34311634490880. Its totient is φ = 28891347618816.
The previous prime is 31551205450217. The next prime is 31551205450273. The reversal of 31551205450243 is 34205450215513.
It is a cyclic number.
It is not a de Polignac number, because 31551205450243 - 213 = 31551205442051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31551205450196 and 31551205450205.
It is not an unprimeable number, because it can be changed into a prime (31551205450273) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12649630 + ... + 14937052.
It is an arithmetic number, because the mean of its divisors is an integer number (2144477155680).
Almost surely, 231551205450243 is an apocalyptic number.
31551205450243 is a deficient number, since it is larger than the sum of its proper divisors (2760429040637).
31551205450243 is a wasteful number, since it uses less digits than its factorization.
31551205450243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2309406.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 31551205450243 its reverse (34205450215513), we get a palindrome (65756655665756).
The spelling of 31551205450243 in words is "thirty-one trillion, five hundred fifty-one billion, two hundred five million, four hundred fifty thousand, two hundred forty-three".
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