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3155165043713 is a prime number
BaseRepresentation
bin101101111010011110011…
…111011101110000000001
3102011122000212200012021222
4231322132133131300001
5403143234222344323
610413243544524425
7443644634236604
oct55723637356001
912148025605258
103155165043713
1110071094596a1
1242b5aa480715
1319b6b91a6337
14ac9d462c33b
15571169cb9c8
hex2de9e7ddc01

3155165043713 has 2 divisors, whose sum is σ = 3155165043714. Its totient is φ = 3155165043712.

The previous prime is 3155165043571. The next prime is 3155165043727. The reversal of 3155165043713 is 3173405615513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1619528576449 + 1535636467264 = 1272607^2 + 1239208^2 .

It is a cyclic number.

It is not a de Polignac number, because 3155165043713 - 216 = 3155164978177 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (3155165043743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1577582521856 + 1577582521857.

It is an arithmetic number, because the mean of its divisors is an integer number (1577582521857).

Almost surely, 23155165043713 is an apocalyptic number.

It is an amenable number.

3155165043713 is a deficient number, since it is larger than the sum of its proper divisors (1).

3155165043713 is an equidigital number, since it uses as much as digits as its factorization.

3155165043713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 567000, while the sum is 44.

The spelling of 3155165043713 in words is "three trillion, one hundred fifty-five billion, one hundred sixty-five million, forty-three thousand, seven hundred thirteen".