Base | Representation |
---|---|
bin | 1001001011101110100… |
… | …10101111011111000001 |
3 | 1010011110002220201110211 |
4 | 10211313102233133001 |
5 | 20132203201430101 |
6 | 400542044554121 |
7 | 31540140604144 |
oct | 4456722573701 |
9 | 1104402821424 |
10 | 315534014401 |
11 | 1118a97a8231 |
12 | 5119b852941 |
13 | 239a71abcc8 |
14 | 113b425405b |
15 | 831b309c51 |
hex | 49774af7c1 |
315534014401 has 8 divisors (see below), whose sum is σ = 319487855400. Its totient is φ = 311604655872.
The previous prime is 315534014387. The next prime is 315534014431. The reversal of 315534014401 is 104410435513.
It can be written as a sum of positive squares in 4 ways, for example, as 17259653376 + 298274361025 = 131376^2 + 546145^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 315534014401 - 213 = 315534006209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (315534014431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6094680 + ... + 6146233.
It is an arithmetic number, because the mean of its divisors is an integer number (39935981925).
Almost surely, 2315534014401 is an apocalyptic number.
It is an amenable number.
315534014401 is a deficient number, since it is larger than the sum of its proper divisors (3953840999).
315534014401 is a wasteful number, since it uses less digits than its factorization.
315534014401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12241235.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 315534014401 its reverse (104410435513), we get a palindrome (419944449914).
The spelling of 315534014401 in words is "three hundred fifteen billion, five hundred thirty-four million, fourteen thousand, four hundred one".
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