Base | Representation |
---|---|
bin | 100011110111111100000001… |
… | …1110000110001111001110001 |
3 | 1112101021102002100222211120202 |
4 | 1013233320003300301321301 |
5 | 312324443040422343311 |
6 | 3035042134252044545 |
7 | 123315554430454112 |
oct | 10757700360617161 |
9 | 1471242070884522 |
10 | 315551310356081 |
11 | 915a9617321458 |
12 | 2b483b5b463755 |
13 | 1070c48cb349b7 |
14 | 57cca9ccba209 |
15 | 2673331534e3b |
hex | 11efe03c31e71 |
315551310356081 has 2 divisors, whose sum is σ = 315551310356082. Its totient is φ = 315551310356080.
The previous prime is 315551310355979. The next prime is 315551310356123. The reversal of 315551310356081 is 180653013155513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 315516744109681 + 34566246400 = 17762791^2 + 185920^2 .
It is a cyclic number.
It is not a de Polignac number, because 315551310356081 - 218 = 315551310093937 is a prime.
It is a super-2 number, since 2×3155513103560812 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (315551300356081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157775655178040 + 157775655178041.
It is an arithmetic number, because the mean of its divisors is an integer number (157775655178041).
Almost surely, 2315551310356081 is an apocalyptic number.
It is an amenable number.
315551310356081 is a deficient number, since it is larger than the sum of its proper divisors (1).
315551310356081 is an equidigital number, since it uses as much as digits as its factorization.
315551310356081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810000, while the sum is 47.
The spelling of 315551310356081 in words is "three hundred fifteen trillion, five hundred fifty-one billion, three hundred ten million, three hundred fifty-six thousand, eighty-one".
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