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315631975502017 is a prime number
BaseRepresentation
bin100011111000100001100101…
…1110001111001000011000001
31112101120010022001200211021101
41013301003023301321003001
5312332303241212031032
63035143154450054401
7123324441410053516
oct10761031361710301
91471503261624241
10315631975502017
119162a850731519
122b497711b7a401
1310716c769c4695
1457d295211930d
1526754a30ddde7
hex11f10cbc790c1

315631975502017 has 2 divisors, whose sum is σ = 315631975502018. Its totient is φ = 315631975502016.

The previous prime is 315631975501987. The next prime is 315631975502083. The reversal of 315631975502017 is 710205579136513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 224756345999376 + 90875629502641 = 14991876^2 + 9532871^2 .

It is a cyclic number.

It is not a de Polignac number, because 315631975502017 - 235 = 315597615763649 is a prime.

It is a super-3 number, since 3×3156319755020173 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (315631975502717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157815987751008 + 157815987751009.

It is an arithmetic number, because the mean of its divisors is an integer number (157815987751009).

Almost surely, 2315631975502017 is an apocalyptic number.

It is an amenable number.

315631975502017 is a deficient number, since it is larger than the sum of its proper divisors (1).

315631975502017 is an equidigital number, since it uses as much as digits as its factorization.

315631975502017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5953500, while the sum is 55.

The spelling of 315631975502017 in words is "three hundred fifteen trillion, six hundred thirty-one billion, nine hundred seventy-five million, five hundred two thousand, seventeen".