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3156480681217 = 5953499672563
BaseRepresentation
bin101101111011101100111…
…010001110010100000001
3102011202102120021111122221
4231323230322032110001
5403203433023244332
610414022303331041
7444022351046503
oct55735472162401
912152376244587
103156480681217
111007724067616
1242b8b6bb0a81
1319b868927b76
14acabb25dd73
155719225a297
hex2deece8e501

3156480681217 has 4 divisors (see below), whose sum is σ = 3209980353840. Its totient is φ = 3102981008596.

The previous prime is 3156480681203. The next prime is 3156480681223. The reversal of 3156480681217 is 7121860846513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3156480681217 is a prime.

It is a super-2 number, since 2×31564806812172 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3156480681227) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26749836223 + ... + 26749836340.

It is an arithmetic number, because the mean of its divisors is an integer number (802495088460).

Almost surely, 23156480681217 is an apocalyptic number.

It is an amenable number.

3156480681217 is a deficient number, since it is larger than the sum of its proper divisors (53499672623).

3156480681217 is an equidigital number, since it uses as much as digits as its factorization.

3156480681217 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53499672622.

The product of its (nonzero) digits is 1935360, while the sum is 52.

The spelling of 3156480681217 in words is "three trillion, one hundred fifty-six billion, four hundred eighty million, six hundred eighty-one thousand, two hundred seventeen".

Divisors: 1 59 53499672563 3156480681217