Base | Representation |
---|---|
bin | 11101011011100100… |
… | …001011010110100011 |
3 | 10000120022211011222221 |
4 | 131123210023112203 |
5 | 1004204322401121 |
6 | 22303422411511 |
7 | 2166046624066 |
oct | 353344132643 |
9 | 100508734887 |
10 | 31600981411 |
11 | 12446a2606a |
12 | 615b130b97 |
13 | 2c97c8278c |
14 | 175ad168dd |
15 | c4e46db41 |
hex | 75b90b5a3 |
31600981411 has 2 divisors, whose sum is σ = 31600981412. Its totient is φ = 31600981410.
The previous prime is 31600981397. The next prime is 31600981421. The reversal of 31600981411 is 11418900613.
It is a strong prime.
It is an emirp because it is prime and its reverse (11418900613) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31600981411 - 213 = 31600973219 is a prime.
It is a super-2 number, since 2×316009814112 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31600981421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15800490705 + 15800490706.
It is an arithmetic number, because the mean of its divisors is an integer number (15800490706).
Almost surely, 231600981411 is an apocalyptic number.
31600981411 is a deficient number, since it is larger than the sum of its proper divisors (1).
31600981411 is an equidigital number, since it uses as much as digits as its factorization.
31600981411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 34.
The spelling of 31600981411 in words is "thirty-one billion, six hundred million, nine hundred eighty-one thousand, four hundred eleven".
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