Search a number
-
+
316114000841 = 714452309871
BaseRepresentation
bin1001001100110011101…
…11001101101111001001
31010012221112021002022002
410212121313031233021
520134400141011331
6401115404040345
731560412446542
oct4463167155711
91105845232262
10316114000841
11112077126671
1251321b330b5
1323a6a3bb252
141142b2ab4c9
1583521c29cb
hex4999dcdbc9

316114000841 has 4 divisors (see below), whose sum is σ = 320566310784. Its totient is φ = 311661690900.

The previous prime is 316114000789. The next prime is 316114000847. The reversal of 316114000841 is 148000411613.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 316114000841 - 238 = 41236093897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (316114000847) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2226154865 + ... + 2226155006.

It is an arithmetic number, because the mean of its divisors is an integer number (80141577696).

Almost surely, 2316114000841 is an apocalyptic number.

It is an amenable number.

316114000841 is a deficient number, since it is larger than the sum of its proper divisors (4452309943).

316114000841 is an equidigital number, since it uses as much as digits as its factorization.

316114000841 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4452309942.

The product of its (nonzero) digits is 2304, while the sum is 29.

The spelling of 316114000841 in words is "three hundred sixteen billion, one hundred fourteen million, eight hundred forty-one", and thus it is an aban number.

Divisors: 1 71 4452309871 316114000841