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3161315182241 is a prime number
BaseRepresentation
bin101110000000001101000…
…100011000011010100001
3102012012220111020121022102
4232000031010120122201
5403243333141312431
610420142123420145
7444253223452616
oct56001504303241
912165814217272
103161315182241
111009785006807
12430826084655
1319c1593bc068
14ad01936050d
15573768bedcb
hex2e00d1186a1

3161315182241 has 2 divisors, whose sum is σ = 3161315182242. Its totient is φ = 3161315182240.

The previous prime is 3161315182189. The next prime is 3161315182253. The reversal of 3161315182241 is 1422815131613.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2993346356641 + 167968825600 = 1730129^2 + 409840^2 .

It is a cyclic number.

It is not a de Polignac number, because 3161315182241 - 222 = 3161310987937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3161315182195 and 3161315182204.

It is not a weakly prime, because it can be changed into another prime (3161315182841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1580657591120 + 1580657591121.

It is an arithmetic number, because the mean of its divisors is an integer number (1580657591121).

Almost surely, 23161315182241 is an apocalyptic number.

It is an amenable number.

3161315182241 is a deficient number, since it is larger than the sum of its proper divisors (1).

3161315182241 is an equidigital number, since it uses as much as digits as its factorization.

3161315182241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 38.

The spelling of 3161315182241 in words is "three trillion, one hundred sixty-one billion, three hundred fifteen million, one hundred eighty-two thousand, two hundred forty-one".