Base | Representation |
---|---|
bin | 1110011000000110100111… |
… | …10101000111001010110001 |
3 | 11010221022120210010220110121 |
4 | 13030003103311013022301 |
5 | 13120433010340323004 |
6 | 151123301252330241 |
7 | 6442034052313006 |
oct | 714032365071261 |
9 | 133838523126417 |
10 | 31614513214129 |
11 | a08970458008a |
12 | 3667130613981 |
13 | 148430b0a4a51 |
14 | 7b42173858ad |
15 | 39c5755b9854 |
hex | 1cc0d3d472b1 |
31614513214129 has 2 divisors, whose sum is σ = 31614513214130. Its totient is φ = 31614513214128.
The previous prime is 31614513214099. The next prime is 31614513214139. The reversal of 31614513214129 is 92141231541613.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19283691342400 + 12330821871729 = 4391320^2 + 3511527^2 .
It is an emirp because it is prime and its reverse (92141231541613) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31614513214129 - 223 = 31614504825521 is a prime.
It is not a weakly prime, because it can be changed into another prime (31614513214139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15807256607064 + 15807256607065.
It is an arithmetic number, because the mean of its divisors is an integer number (15807256607065).
Almost surely, 231614513214129 is an apocalyptic number.
It is an amenable number.
31614513214129 is a deficient number, since it is larger than the sum of its proper divisors (1).
31614513214129 is an equidigital number, since it uses as much as digits as its factorization.
31614513214129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 43.
The spelling of 31614513214129 in words is "thirty-one trillion, six hundred fourteen billion, five hundred thirteen million, two hundred fourteen thousand, one hundred twenty-nine".
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