Base | Representation |
---|---|
bin | 1001001100111001010… |
… | …11010001101110111011 |
3 | 1010020001211002012200001 |
4 | 10212130223101232323 |
5 | 20134444232000011 |
6 | 401124211453431 |
7 | 31561524612544 |
oct | 4463453215673 |
9 | 1106054065601 |
10 | 316161203131 |
11 | 1120a0836424 |
12 | 513358b7277 |
13 | 23a771070b7 |
14 | 114336774cb |
15 | 83563e87c1 |
hex | 499cad1bbb |
316161203131 has 2 divisors, whose sum is σ = 316161203132. Its totient is φ = 316161203130.
The previous prime is 316161203069. The next prime is 316161203143. The reversal of 316161203131 is 131302161613.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 316161203131 - 29 = 316161202619 is a prime.
It is a super-2 number, since 2×3161612031312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 316161203131.
It is not a weakly prime, because it can be changed into another prime (316161203191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158080601565 + 158080601566.
It is an arithmetic number, because the mean of its divisors is an integer number (158080601566).
Almost surely, 2316161203131 is an apocalyptic number.
316161203131 is a deficient number, since it is larger than the sum of its proper divisors (1).
316161203131 is an equidigital number, since it uses as much as digits as its factorization.
316161203131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 28.
Adding to 316161203131 its reverse (131302161613), we get a palindrome (447463364744).
The spelling of 316161203131 in words is "three hundred sixteen billion, one hundred sixty-one million, two hundred three thousand, one hundred thirty-one".
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