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316253305510411 is a prime number
BaseRepresentation
bin100011111101000010111010…
…1111011110001101000001011
31112110202112001121201120112111
41013322011311323301220023
5312422443232202313121
63040340432440323151
7123420355505021113
oct10772056573615013
91473675047646474
10316253305510411
119184a301288025
122b5780141734b7
1310760735740519
145814a55178043
15268671a8442e1
hex11fa175ef1a0b

316253305510411 has 2 divisors, whose sum is σ = 316253305510412. Its totient is φ = 316253305510410.

The previous prime is 316253305510393. The next prime is 316253305510463. The reversal of 316253305510411 is 114015503352613.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 316253305510411 - 25 = 316253305510379 is a prime.

It is a super-4 number, since 4×3162533055104114 (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (316253305510111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158126652755205 + 158126652755206.

It is an arithmetic number, because the mean of its divisors is an integer number (158126652755206).

Almost surely, 2316253305510411 is an apocalyptic number.

316253305510411 is a deficient number, since it is larger than the sum of its proper divisors (1).

316253305510411 is an equidigital number, since it uses as much as digits as its factorization.

316253305510411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162000, while the sum is 40.

The spelling of 316253305510411 in words is "three hundred sixteen trillion, two hundred fifty-three billion, three hundred five million, five hundred ten thousand, four hundred eleven".