Base | Representation |
---|---|
bin | 100011111101000100001100… |
… | …1111010001000101101110001 |
3 | 1112110202210011100021120022121 |
4 | 1013322020121322020231301 |
5 | 312423014400433402423 |
6 | 3040342005432434241 |
7 | 123420513621305410 |
oct | 10772103172105561 |
9 | 1473683140246277 |
10 | 316256056544113 |
11 | 918504931603a4 |
12 | 2b578661548981 |
13 | 10760a83684a0a |
14 | 5814c36693477 |
15 | 268682c10a45d |
hex | 11fa219e88b71 |
316256056544113 has 4 divisors (see below), whose sum is σ = 361435493193280. Its totient is φ = 271076619894948.
The previous prime is 316256056544009. The next prime is 316256056544119. The reversal of 316256056544113 is 311445650652613.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 316256056544113 - 229 = 316255519673201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (316256056544119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22589718324573 + ... + 22589718324586.
It is an arithmetic number, because the mean of its divisors is an integer number (90358873298320).
Almost surely, 2316256056544113 is an apocalyptic number.
It is an amenable number.
316256056544113 is a deficient number, since it is larger than the sum of its proper divisors (45179436649167).
316256056544113 is an equidigital number, since it uses as much as digits as its factorization.
316256056544113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45179436649166.
The product of its (nonzero) digits is 7776000, while the sum is 52.
The spelling of 316256056544113 in words is "three hundred sixteen trillion, two hundred fifty-six billion, fifty-six million, five hundred forty-four thousand, one hundred thirteen".
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