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316502711225377 is a prime number
BaseRepresentation
bin100011111110110111000011…
…1101011000100110000100001
31112111122100211010120121211221
41013331232013223010300201
5312441040023033203002
63041051201022335041
7123444365143433335
oct10775560753046041
91474570733517757
10316502711225377
1191936056307116
122b5b841972a481
131077b101654b61
145822b54a8d7c5
15268ce663bdc37
hex11fdb87ac4c21

316502711225377 has 2 divisors, whose sum is σ = 316502711225378. Its totient is φ = 316502711225376.

The previous prime is 316502711225303. The next prime is 316502711225413. The reversal of 316502711225377 is 773522117205613.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 207143739615121 + 109358971610256 = 14392489^2 + 10457484^2 .

It is an emirp because it is prime and its reverse (773522117205613) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 316502711225377 - 243 = 307706618203169 is a prime.

It is not a weakly prime, because it can be changed into another prime (316502711295377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158251355612688 + 158251355612689.

It is an arithmetic number, because the mean of its divisors is an integer number (158251355612689).

Almost surely, 2316502711225377 is an apocalyptic number.

It is an amenable number.

316502711225377 is a deficient number, since it is larger than the sum of its proper divisors (1).

316502711225377 is an equidigital number, since it uses as much as digits as its factorization.

316502711225377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3704400, while the sum is 52.

The spelling of 316502711225377 in words is "three hundred sixteen trillion, five hundred two billion, seven hundred eleven million, two hundred twenty-five thousand, three hundred seventy-seven".