Base | Representation |
---|---|
bin | 100011111111010010010000… |
… | …1110000111111011101010011 |
3 | 1112111211221121111202211101201 |
4 | 1013332210201300333131103 |
5 | 312443014144021331033 |
6 | 3041134102002012031 |
7 | 123451533634616314 |
oct | 10776444160773523 |
9 | 1474757544684351 |
10 | 316561131042643 |
11 | 91958904818533 |
12 | 2b607802347017 |
13 | 107837818c7476 |
14 | 58258d772a60b |
15 | 268e73503947d |
hex | 11fe921c3f753 |
316561131042643 has 4 divisors (see below), whose sum is σ = 316989495226120. Its totient is φ = 316132766859168.
The previous prime is 316561131042617. The next prime is 316561131042649. The reversal of 316561131042643 is 346240131165613.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 316561131042643 - 29 = 316561131042131 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 316561131042593 and 316561131042602.
It is not an unprimeable number, because it can be changed into a prime (316561131042649) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214182090630 + ... + 214182092107.
It is an arithmetic number, because the mean of its divisors is an integer number (79247373806530).
Almost surely, 2316561131042643 is an apocalyptic number.
316561131042643 is a deficient number, since it is larger than the sum of its proper divisors (428364183477).
316561131042643 is an equidigital number, since it uses as much as digits as its factorization.
316561131042643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 428364183476.
The product of its (nonzero) digits is 933120, while the sum is 46.
The spelling of 316561131042643 in words is "three hundred sixteen trillion, five hundred sixty-one billion, one hundred thirty-one million, forty-two thousand, six hundred forty-three".
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