Base | Representation |
---|---|
bin | 1110011011100110000101… |
… | …01001110100100110010001 |
3 | 11011100210020202120200200112 |
4 | 13031303002221310212101 |
5 | 13124414210414013342 |
6 | 151254342025331105 |
7 | 6453512046245444 |
oct | 715630251644621 |
9 | 134323222520615 |
10 | 31734484126097 |
11 | a125578a77a05 |
12 | 3686432636a95 |
13 | 149271a24625c |
14 | 7b9d588b965b |
15 | 3a0747c26682 |
hex | 1cdcc2a74991 |
31734484126097 has 2 divisors, whose sum is σ = 31734484126098. Its totient is φ = 31734484126096.
The previous prime is 31734484126091. The next prime is 31734484126129. The reversal of 31734484126097 is 79062148443713.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26475974721361 + 5258509404736 = 5145481^2 + 2293144^2 .
It is a cyclic number.
It is not a de Polignac number, because 31734484126097 - 212 = 31734484122001 is a prime.
It is not a weakly prime, because it can be changed into another prime (31734484126091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15867242063048 + 15867242063049.
It is an arithmetic number, because the mean of its divisors is an integer number (15867242063049).
Almost surely, 231734484126097 is an apocalyptic number.
It is an amenable number.
31734484126097 is a deficient number, since it is larger than the sum of its proper divisors (1).
31734484126097 is an equidigital number, since it uses as much as digits as its factorization.
31734484126097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24385536, while the sum is 59.
The spelling of 31734484126097 in words is "thirty-one trillion, seven hundred thirty-four billion, four hundred eighty-four million, one hundred twenty-six thousand, ninety-seven".
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