Base | Representation |
---|---|
bin | 11101100110001100… |
… | …001011110101100001 |
3 | 10001000202020201121112 |
4 | 131212030023311201 |
5 | 1010040441210223 |
6 | 22333231233105 |
7 | 2203343044211 |
oct | 354614136541 |
9 | 101022221545 |
10 | 31779241313 |
11 | 1252860a3a6 |
12 | 61aa978795 |
13 | 2cc5b97601 |
14 | 177687a241 |
15 | c5ee31778 |
hex | 76630bd61 |
31779241313 has 2 divisors, whose sum is σ = 31779241314. Its totient is φ = 31779241312.
The previous prime is 31779241267. The next prime is 31779241321. The reversal of 31779241313 is 31314297713.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31729228129 + 50013184 = 178127^2 + 7072^2 .
It is an emirp because it is prime and its reverse (31314297713) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31779241313 is a prime.
It is not a weakly prime, because it can be changed into another prime (31779241393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15889620656 + 15889620657.
It is an arithmetic number, because the mean of its divisors is an integer number (15889620657).
Almost surely, 231779241313 is an apocalyptic number.
It is an amenable number.
31779241313 is a deficient number, since it is larger than the sum of its proper divisors (1).
31779241313 is an equidigital number, since it uses as much as digits as its factorization.
31779241313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 95256, while the sum is 41.
The spelling of 31779241313 in words is "thirty-one billion, seven hundred seventy-nine million, two hundred forty-one thousand, three hundred thirteen".
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