Base | Representation |
---|---|
bin | 101110100100001110001… |
… | …001001001001100001011 |
3 | 102022220201122210220100202 |
4 | 232210032021021030023 |
5 | 404412033401212413 |
6 | 10450015410322415 |
7 | 450122453321324 |
oct | 56441611111413 |
9 | 12286648726322 |
10 | 3199987913483 |
11 | 102411a832119 |
12 | 43821958940b |
13 | 1a29b04a989a |
14 | b0c4754d44b |
15 | 5838bacbe58 |
hex | 2e90e24930b |
3199987913483 has 2 divisors, whose sum is σ = 3199987913484. Its totient is φ = 3199987913482.
The previous prime is 3199987913449. The next prime is 3199987913527. The reversal of 3199987913483 is 3843197899913.
It is a weak prime.
It is an emirp because it is prime and its reverse (3843197899913) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3199987913483 - 212 = 3199987909387 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3199987913483.
It is not a weakly prime, because it can be changed into another prime (3199987913783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1599993956741 + 1599993956742.
It is an arithmetic number, because the mean of its divisors is an integer number (1599993956742).
Almost surely, 23199987913483 is an apocalyptic number.
3199987913483 is a deficient number, since it is larger than the sum of its proper divisors (1).
3199987913483 is an equidigital number, since it uses as much as digits as its factorization.
3199987913483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 317447424, while the sum is 74.
The spelling of 3199987913483 in words is "three trillion, one hundred ninety-nine billion, nine hundred eighty-seven million, nine hundred thirteen thousand, four hundred eighty-three".
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