Base | Representation |
---|---|
bin | 101110100100001111011… |
… | …101110010001011001011 |
3 | 102022220210012120011112100 |
4 | 232210033131302023023 |
5 | 404412110041221301 |
6 | 10450021522044443 |
7 | 450123143032302 |
oct | 56441735621313 |
9 | 12286705504470 |
10 | 3200010101451 |
11 | 1024131307289 |
12 | 438224aa9723 |
13 | 1a29b4c77b67 |
14 | b0c4a487439 |
15 | 5838da11286 |
hex | 2e90f7722cb |
3200010101451 has 24 divisors (see below), whose sum is σ = 4741112295920. Its totient is φ = 2079116164800.
The previous prime is 3200010101447. The next prime is 3200010101489. The reversal of 3200010101451 is 1541010100023.
3200010101451 is a `hidden beast` number, since 3 + 200 + 0 + 1 + 0 + 10 + 1 + 451 = 666.
3200010101451 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3200010101451 - 22 = 3200010101447 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3200010101441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26677765 + ... + 26797446.
Almost surely, 23200010101451 is an apocalyptic number.
3200010101451 is a deficient number, since it is larger than the sum of its proper divisors (1541102194469).
3200010101451 is a wasteful number, since it uses less digits than its factorization.
3200010101451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53475387 (or 53475384 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
Adding to 3200010101451 its reverse (1541010100023), we get a palindrome (4741020201474).
The spelling of 3200010101451 in words is "three trillion, two hundred billion, ten million, one hundred one thousand, four hundred fifty-one".
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