Base | Representation |
---|---|
bin | 101110100100001111100… |
… | …101000100000111101011 |
3 | 102022220210100011010111222 |
4 | 232210033211010013223 |
5 | 404412111033304323 |
6 | 10450022031012255 |
7 | 450123165201416 |
oct | 56441745040753 |
9 | 12286710133458 |
10 | 3200012009963 |
11 | 10241323a016a |
12 | 43822566a08b |
13 | 1a29b5495762 |
14 | b0c4a822b7d |
15 | 5838dc8b9c8 |
hex | 2e90f9441eb |
3200012009963 has 2 divisors, whose sum is σ = 3200012009964. Its totient is φ = 3200012009962.
The previous prime is 3200012009941. The next prime is 3200012010029. The reversal of 3200012009963 is 3699002100023.
3200012009963 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3200012009963 - 212 = 3200012005867 is a prime.
It is a super-2 number, since 2×32000120099632 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3200012009903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600006004981 + 1600006004982.
It is an arithmetic number, because the mean of its divisors is an integer number (1600006004982).
Almost surely, 23200012009963 is an apocalyptic number.
3200012009963 is a deficient number, since it is larger than the sum of its proper divisors (1).
3200012009963 is an equidigital number, since it uses as much as digits as its factorization.
3200012009963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 35.
Adding to 3200012009963 its reverse (3699002100023), we get a palindrome (6899014109986).
The spelling of 3200012009963 in words is "three trillion, two hundred billion, twelve million, nine thousand, nine hundred sixty-three".
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