Base | Representation |
---|---|
bin | 1001010100000011010… |
… | …11000100100000011001 |
3 | 1010120222120100101111021 |
4 | 10222001223010200121 |
5 | 20220331300201132 |
6 | 403001333402441 |
7 | 32055655510624 |
oct | 4520153044031 |
9 | 1116876311437 |
10 | 320003131417 |
11 | 113792474a72 |
12 | 52028499421 |
13 | 2423a061948 |
14 | 116b9a00dbb |
15 | 84cd847997 |
hex | 4a81ac4819 |
320003131417 has 2 divisors, whose sum is σ = 320003131418. Its totient is φ = 320003131416.
The previous prime is 320003131391. The next prime is 320003131477. The reversal of 320003131417 is 714131300023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 306726561241 + 13276570176 = 553829^2 + 115224^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-320003131417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 320003131391 and 320003131400.
It is not a weakly prime, because it can be changed into another prime (320003131477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160001565708 + 160001565709.
It is an arithmetic number, because the mean of its divisors is an integer number (160001565709).
Almost surely, 2320003131417 is an apocalyptic number.
It is an amenable number.
320003131417 is a deficient number, since it is larger than the sum of its proper divisors (1).
320003131417 is an equidigital number, since it uses as much as digits as its factorization.
320003131417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
The spelling of 320003131417 in words is "three hundred twenty billion, three million, one hundred thirty-one thousand, four hundred seventeen".
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