320004111254031 has 48 divisors (see below), whose sum is σ = 488659879749600. Its totient is φ = 201233979058176.

The previous prime is 320004111253999. The next prime is 320004111254077. The reversal of 320004111254031 is 130452111400023.

320004111254031 is a `hidden beast` number, since 3 + 2 + 0 + 0 + 0 + 4 + 1 + 112 + 540 + 3 + 1 = 666.

It is not a de Polignac number, because 320004111254031 - 2⁵ = 320004111253999 is a prime.

It is a super-2 number, since 2×320004111254031² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 320004111253986 and 320004111254004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (320004111254081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1442564281 + ... + 1442786093.

It is an arithmetic number, because the mean of its divisors is an integer number (10180414161450).

Almost surely, 2^{320004111254031} is an apocalyptic number.

320004111254031 is a deficient number, since it is larger than the sum of its proper divisors (168655768495569).

320004111254031 is a wasteful number, since it uses less digits than its factorization.

320004111254031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 258280 (or 258277 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 320004111254031 its reverse (130452111400023), we get a palindrome (450456222654054).

The spelling of 320004111254031 in words is "three hundred twenty trillion, four billion, one hundred eleven million, two hundred fifty-four thousand, thirty-one".