Base | Representation |
---|---|
bin | 100100011000011101011111… |
… | …1001000111000000011011011 |
3 | 1112222002201201001120210002102 |
4 | 1020300322333020320003123 |
5 | 313421211424304444323 |
6 | 3052343415140354015 |
7 | 124256525106523046 |
oct | 11060727710700333 |
9 | 1488081631523072 |
10 | 320021219999963 |
11 | 92a72267832609 |
12 | 2ba8630b0a590b |
13 | 10974b43a6b041 |
14 | 5905176dd3c5d |
15 | 26ee7465ec328 |
hex | 1230ebf2380db |
320021219999963 has 2 divisors, whose sum is σ = 320021219999964. Its totient is φ = 320021219999962.
The previous prime is 320021219999891. The next prime is 320021220000007. The reversal of 320021219999963 is 369999912120023.
It is a strong prime.
It is an emirp because it is prime and its reverse (369999912120023) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-320021219999963 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 320021219999963.
It is not a weakly prime, because it can be changed into another prime (320021219939963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160010609999981 + 160010609999982.
It is an arithmetic number, because the mean of its divisors is an integer number (160010609999982).
Almost surely, 2320021219999963 is an apocalyptic number.
320021219999963 is a deficient number, since it is larger than the sum of its proper divisors (1).
320021219999963 is an equidigital number, since it uses as much as digits as its factorization.
320021219999963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25509168, while the sum is 65.
The spelling of 320021219999963 in words is "three hundred twenty trillion, twenty-one billion, two hundred nineteen million, nine hundred ninety-nine thousand, nine hundred sixty-three".
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