Base | Representation |
---|---|
bin | 101110100101001011010… |
… | …001000101011011100011 |
3 | 102100000101010110021211021 |
4 | 232211023101011123203 |
5 | 404421133412433121 |
6 | 10450305242230311 |
7 | 450160045003603 |
oct | 56451321053343 |
9 | 12300333407737 |
10 | 3201013405411 |
11 | 10245a6687408 |
12 | 438464ab5397 |
13 | 1a2b14aa0b43 |
14 | b0d03814c03 |
15 | 583ebb46641 |
hex | 2e94b4456e3 |
3201013405411 has 2 divisors, whose sum is σ = 3201013405412. Its totient is φ = 3201013405410.
The previous prime is 3201013405397. The next prime is 3201013405427. The reversal of 3201013405411 is 1145043101023.
3201013405411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3201013405411 - 221 = 3201011308259 is a prime.
It is not a weakly prime, because it can be changed into another prime (3201013405211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600506702705 + 1600506702706.
It is an arithmetic number, because the mean of its divisors is an integer number (1600506702706).
Almost surely, 23201013405411 is an apocalyptic number.
3201013405411 is a deficient number, since it is larger than the sum of its proper divisors (1).
3201013405411 is an equidigital number, since it uses as much as digits as its factorization.
3201013405411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 3201013405411 its reverse (1145043101023), we get a palindrome (4346056506434).
The spelling of 3201013405411 in words is "three trillion, two hundred one billion, thirteen million, four hundred five thousand, four hundred eleven".
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