Base | Representation |
---|---|
bin | 101110100101011101000… |
… | …000011100011100011001 |
3 | 102100001010212111100021111 |
4 | 232211131000130130121 |
5 | 404422241111024423 |
6 | 10450354553340321 |
7 | 450200320543054 |
oct | 56453500343431 |
9 | 12301125440244 |
10 | 3201311033113 |
11 | 1024739690516 |
12 | 4385287076a1 |
13 | 1a2b6164abcb |
14 | b0d3116ba9b |
15 | 58417d3760d |
hex | 2e95d01c719 |
3201311033113 has 2 divisors, whose sum is σ = 3201311033114. Its totient is φ = 3201311033112.
The previous prime is 3201311033069. The next prime is 3201311033117. The reversal of 3201311033113 is 3113301131023.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2208514015449 + 992797017664 = 1486107^2 + 996392^2 .
It is a cyclic number.
It is not a de Polignac number, because 3201311033113 - 225 = 3201277478681 is a prime.
It is not a weakly prime, because it can be changed into another prime (3201311033117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600655516556 + 1600655516557.
It is an arithmetic number, because the mean of its divisors is an integer number (1600655516557).
Almost surely, 23201311033113 is an apocalyptic number.
It is an amenable number.
3201311033113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3201311033113 is an equidigital number, since it uses as much as digits as its factorization.
3201311033113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 3201311033113 its reverse (3113301131023), we get a palindrome (6314612164136).
The spelling of 3201311033113 in words is "three trillion, two hundred one billion, three hundred eleven million, thirty-three thousand, one hundred thirteen".
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