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320131313122 = 2160065656561
BaseRepresentation
bin1001010100010010101…
…00000010110111100010
31010121022111112200201211
410222021110002313202
520221112104004442
6403022153020334
732062103156335
oct4521124026742
91117274480654
10320131313122
11113848864865
12520633b46aa
132425a7918ca
14116cca4a61c
1584d9c17617
hex4a89502de2

320131313122 has 4 divisors (see below), whose sum is σ = 480196969686. Its totient is φ = 160065656560.

The previous prime is 320131313119. The next prime is 320131313191. The reversal of 320131313122 is 221313131023.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 221313131023 = 1491485323027.

It can be written as a sum of positive squares in only one way, i.e., 294828366361 + 25302946761 = 542981^2 + 159069^2 .

It is a junction number, because it is equal to n+sod(n) for n = 320131313093 and 320131313102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80032828279 + ... + 80032828282.

Almost surely, 2320131313122 is an apocalyptic number.

320131313122 is a deficient number, since it is larger than the sum of its proper divisors (160065656564).

320131313122 is a wasteful number, since it uses less digits than its factorization.

320131313122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 160065656563.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 320131313122 its reverse (221313131023), we get a palindrome (541444444145).

The spelling of 320131313122 in words is "three hundred twenty billion, one hundred thirty-one million, three hundred thirteen thousand, one hundred twenty-two".

Divisors: 1 2 160065656561 320131313122