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320134143320041 is a prime number
BaseRepresentation
bin100100011001010010000100…
…1111001001001111111101001
31112222111112011212201210201111
41020302210021321021333221
5313430034211142220131
63052511332315150321
7124300633336101421
oct11062441171117751
91488445155653644
10320134143320041
119300614502a326
122baa4184a453a1
131098269bab232b
14590a80a53d481
15270265518dab1
hex1232909e49fe9

320134143320041 has 2 divisors, whose sum is σ = 320134143320042. Its totient is φ = 320134143320040.

The previous prime is 320134143319997. The next prime is 320134143320051. The reversal of 320134143320041 is 140023341431023.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 263526652118016 + 56607491202025 = 16233504^2 + 7523795^2 .

It is a cyclic number.

It is not a de Polignac number, because 320134143320041 - 225 = 320134109765609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 320134143319985 and 320134143320012.

It is not a weakly prime, because it can be changed into another prime (320134143320051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160067071660020 + 160067071660021.

It is an arithmetic number, because the mean of its divisors is an integer number (160067071660021).

Almost surely, 2320134143320041 is an apocalyptic number.

It is an amenable number.

320134143320041 is a deficient number, since it is larger than the sum of its proper divisors (1).

320134143320041 is an equidigital number, since it uses as much as digits as its factorization.

320134143320041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 320134143320041 its reverse (140023341431023), we get a palindrome (460157484751064).

The spelling of 320134143320041 in words is "three hundred twenty trillion, one hundred thirty-four billion, one hundred forty-three million, three hundred twenty thousand, forty-one".