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320145433 = 3071042819
BaseRepresentation
bin10011000101010…
…000100000011001
3211022102001222021
4103011100200121
51123424123213
651433454441
710635122416
oct2305204031
9738361867
10320145433
11154794003
128b271421
135143248a
143073910d
151d18cd8d
hex13150819

320145433 has 4 divisors (see below), whose sum is σ = 321188560. Its totient is φ = 319102308.

The previous prime is 320145407. The next prime is 320145467. The reversal of 320145433 is 334541023.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334541023 = 2271473749.

It is a cyclic number.

It is not a de Polignac number, because 320145433 - 29 = 320144921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 320145398 and 320145407.

It is not an unprimeable number, because it can be changed into a prime (320145473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 521103 + ... + 521716.

It is an arithmetic number, because the mean of its divisors is an integer number (80297140).

Almost surely, 2320145433 is an apocalyptic number.

It is an amenable number.

320145433 is a deficient number, since it is larger than the sum of its proper divisors (1043127).

320145433 is a wasteful number, since it uses less digits than its factorization.

320145433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1043126.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 320145433 is about 17892.6083341697. The cubic root of 320145433 is about 684.0939825320.

Adding to 320145433 its reverse (334541023), we get a palindrome (654686456).

The spelling of 320145433 in words is "three hundred twenty million, one hundred forty-five thousand, four hundred thirty-three".

Divisors: 1 307 1042819 320145433