Base | Representation |
---|---|
bin | 1001010100101011101… |
… | …01101010101001111001 |
3 | 1010121212010221221001022 |
4 | 10222111311222221321 |
5 | 20222024403002213 |
6 | 403055101032225 |
7 | 32100234266321 |
oct | 4522565525171 |
9 | 1117763857038 |
10 | 320341453433 |
11 | 113946443341 |
12 | 52101855675 |
13 | 242921895a1 |
14 | 1170c90c281 |
15 | 84ed3c6308 |
hex | 4a95d6aa79 |
320341453433 has 2 divisors, whose sum is σ = 320341453434. Its totient is φ = 320341453432.
The previous prime is 320341453391. The next prime is 320341453541. The reversal of 320341453433 is 334354143023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 201352330729 + 118989122704 = 448723^2 + 344948^2 .
It is a cyclic number.
It is not a de Polignac number, because 320341453433 - 216 = 320341387897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 320341453393 and 320341453402.
It is not a weakly prime, because it can be changed into another prime (320341455433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160170726716 + 160170726717.
It is an arithmetic number, because the mean of its divisors is an integer number (160170726717).
Almost surely, 2320341453433 is an apocalyptic number.
It is an amenable number.
320341453433 is a deficient number, since it is larger than the sum of its proper divisors (1).
320341453433 is an equidigital number, since it uses as much as digits as its factorization.
320341453433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 35.
Adding to 320341453433 its reverse (334354143023), we get a palindrome (654695596456).
The spelling of 320341453433 in words is "three hundred twenty billion, three hundred forty-one million, four hundred fifty-three thousand, four hundred thirty-three".
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