Base | Representation |
---|---|
bin | 1110100100011111011000… |
… | …00010100000100001010010 |
3 | 11012110000011010112202121121 |
4 | 13102033230002200201102 |
5 | 13144421132003010310 |
6 | 152051010051312454 |
7 | 6514552033101631 |
oct | 722175402404122 |
9 | 135400133482547 |
10 | 32040121141330 |
11 | a233159111185 |
12 | 371570b8ab72a |
13 | 14b54a7b8c423 |
14 | 7caa7053d518 |
15 | 3a868521c0da |
hex | 1d23ec0a0852 |
32040121141330 has 16 divisors (see below), whose sum is σ = 59013432428544. Its totient is φ = 12518000817840.
The previous prime is 32040121141313. The next prime is 32040121141337. The reversal of 32040121141330 is 3314112104023.
It is a super-2 number, since 2×320401211413302 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32040121141295 and 32040121141304.
It is not an unprimeable number, because it can be changed into a prime (32040121141337) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37255954386 + ... + 37255955245.
It is an arithmetic number, because the mean of its divisors is an integer number (3688339526784).
Almost surely, 232040121141330 is an apocalyptic number.
32040121141330 is a deficient number, since it is larger than the sum of its proper divisors (26973311287214).
32040121141330 is a wasteful number, since it uses less digits than its factorization.
32040121141330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74511909681.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 32040121141330 its reverse (3314112104023), we get a palindrome (35354233245353).
The spelling of 32040121141330 in words is "thirty-two trillion, forty billion, one hundred twenty-one million, one hundred forty-one thousand, three hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •