Base | Representation |
---|---|
bin | 101110101000001010000… |
… | …100011111111011101001 |
3 | 102100022122012222111121220 |
4 | 232220022010133323221 |
5 | 404444212411214340 |
6 | 10451555034052253 |
7 | 450332265220410 |
oct | 56501204377351 |
9 | 12308565874556 |
10 | 3204214554345 |
11 | 1025999644a42 |
12 | 438bb8b7a089 |
13 | 1a32050525cc |
14 | b1128a1c477 |
15 | 58537bbeed0 |
hex | 2ea0a11fee9 |
3204214554345 has 32 divisors (see below), whose sum is σ = 5864138941440. Its totient is φ = 1463532857280.
The previous prime is 3204214554341. The next prime is 3204214554367. The reversal of 3204214554345 is 5434554124023.
It is not a de Polignac number, because 3204214554345 - 22 = 3204214554341 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3204214554297 and 3204214554306.
It is not an unprimeable number, because it can be changed into a prime (3204214554341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12907075 + ... + 13152984.
It is an arithmetic number, because the mean of its divisors is an integer number (183254341920).
Almost surely, 23204214554345 is an apocalyptic number.
3204214554345 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3204214554345 is a deficient number, since it is larger than the sum of its proper divisors (2659924387095).
3204214554345 is a wasteful number, since it uses less digits than its factorization.
3204214554345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26061245.
The product of its (nonzero) digits is 1152000, while the sum is 42.
Adding to 3204214554345 its reverse (5434554124023), we get a palindrome (8638768678368).
The spelling of 3204214554345 in words is "three trillion, two hundred four billion, two hundred fourteen million, five hundred fifty-four thousand, three hundred forty-five".
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