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32102011413313 is a prime number
BaseRepresentation
bin1110100110010010101001…
…11111001010001101000001
311012122220220101000100001021
413103021110333022031001
513201424404410211223
6152135243242505441
76522202524531442
oct723112477121501
9135586811010037
1032102011413313
11a2574285aa596
123725702805281
1314bb28c12533a
147cda620872c9
153aa0a88aa65d
hex1d3254fca341

32102011413313 has 2 divisors, whose sum is σ = 32102011413314. Its totient is φ = 32102011413312.

The previous prime is 32102011413281. The next prime is 32102011413319. The reversal of 32102011413313 is 31331411020123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30914678649409 + 1187332763904 = 5560097^2 + 1089648^2 .

It is an emirp because it is prime and its reverse (31331411020123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32102011413313 - 25 = 32102011413281 is a prime.

It is not a weakly prime, because it can be changed into another prime (32102011413319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16051005706656 + 16051005706657.

It is an arithmetic number, because the mean of its divisors is an integer number (16051005706657).

Almost surely, 232102011413313 is an apocalyptic number.

It is an amenable number.

32102011413313 is a deficient number, since it is larger than the sum of its proper divisors (1).

32102011413313 is an equidigital number, since it uses as much as digits as its factorization.

32102011413313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 32102011413313 its reverse (31331411020123), we get a palindrome (63433422433436).

The spelling of 32102011413313 in words is "thirty-two trillion, one hundred two billion, eleven million, four hundred thirteen thousand, three hundred thirteen".