Base | Representation |
---|---|
bin | 1001010101111111010… |
… | …00100010011110001001 |
3 | 1010200200000101122220220 |
4 | 10222333220202132021 |
5 | 20224443404430423 |
6 | 403252430140253 |
7 | 32123510354145 |
oct | 4527750423611 |
9 | 1120600348826 |
10 | 321042655113 |
11 | 114176233564 |
12 | 52278651689 |
13 | 2437452991b |
14 | 11777aba225 |
15 | 853ec349e3 |
hex | 4abfa22789 |
321042655113 has 4 divisors (see below), whose sum is σ = 428056873488. Its totient is φ = 214028436740.
The previous prime is 321042655091. The next prime is 321042655133. The reversal of 321042655113 is 311556240123.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 321042655113 - 28 = 321042654857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (321042655133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53507109183 + ... + 53507109188.
It is an arithmetic number, because the mean of its divisors is an integer number (107014218372).
Almost surely, 2321042655113 is an apocalyptic number.
It is an amenable number.
321042655113 is a deficient number, since it is larger than the sum of its proper divisors (107014218375).
321042655113 is a wasteful number, since it uses less digits than its factorization.
321042655113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107014218374.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 321042655113 its reverse (311556240123), we get a palindrome (632598895236).
The spelling of 321042655113 in words is "three hundred twenty-one billion, forty-two million, six hundred fifty-five thousand, one hundred thirteen".
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