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321131332320947 is a prime number
BaseRepresentation
bin100100100000100010011011…
…0111111010011111010110011
31120010000212002200202200100222
41021001010312333103322303
5314042403432033232242
63054553410352203255
7124432654531542011
oct11101046677237263
91503025080680328
10321131332320947
1193360040244a75
12300254a153952b
1310a2572989c3a5
145942ba74db8b1
15271d569c465d2
hex1241136fd3eb3

321131332320947 has 2 divisors, whose sum is σ = 321131332320948. Its totient is φ = 321131332320946.

The previous prime is 321131332320919. The next prime is 321131332321001. The reversal of 321131332320947 is 749023233131123.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-321131332320947 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 321131332320898 and 321131332320907.

It is not a weakly prime, because it can be changed into another prime (321131332320917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565666160473 + 160565666160474.

It is an arithmetic number, because the mean of its divisors is an integer number (160565666160474).

Almost surely, 2321131332320947 is an apocalyptic number.

321131332320947 is a deficient number, since it is larger than the sum of its proper divisors (1).

321131332320947 is an equidigital number, since it uses as much as digits as its factorization.

321131332320947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 489888, while the sum is 44.

The spelling of 321131332320947 in words is "three hundred twenty-one trillion, one hundred thirty-one billion, three hundred thirty-two million, three hundred twenty thousand, nine hundred forty-seven".