321131403002 has 4 divisors (see below), whose sum is σ = 481697104506. Its totient is φ = 160565701500.

The previous prime is 321131403001. The next prime is 321131403007. The reversal of 321131403002 is 200304131123.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 200304131123 = 467 ⋅428916769.

It can be written as a sum of positive squares in only one way, i.e., 247793888521 + 73337514481 = 497789^2 + 270809^2 .

It is a super-2 number, since 2×321131403002² (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (321131403001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80282850749 + ... + 80282850752.

Almost surely, 2^321131403002 is an apocalyptic number.

321131403002 is a deficient number, since it is larger than the sum of its proper divisors (160565701504).

321131403002 is a wasteful number, since it uses less digits than its factorization.

321131403002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 160565701503.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 321131403002 its reverse (200304131123), we get a palindrome (521435534125).

The spelling of 321131403002 in words is "three hundred twenty-one billion, one hundred thirty-one million, four hundred three thousand, two".