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32113312132963 is a prime number
BaseRepresentation
bin1110100110100111101101…
…00011111110111101100011
311012201000001221022101002111
413103103312203332331203
513202121030401223323
6152144352452300151
76523052545212115
oct723236643767543
9135630057271074
1032113312132963
11a2611a7563516
123727937311657
1314bc3704401b9
147d0414c773b5
153aa51aa4bc0d
hex1d34f68fef63

32113312132963 has 2 divisors, whose sum is σ = 32113312132964. Its totient is φ = 32113312132962.

The previous prime is 32113312132931. The next prime is 32113312133009. The reversal of 32113312132963 is 36923121331123.

It is a weak prime.

It is an emirp because it is prime and its reverse (36923121331123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32113312132963 - 25 = 32113312132931 is a prime.

It is a super-2 number, since 2×321133121329632 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (32113312112963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056656066481 + 16056656066482.

It is an arithmetic number, because the mean of its divisors is an integer number (16056656066482).

Almost surely, 232113312132963 is an apocalyptic number.

32113312132963 is a deficient number, since it is larger than the sum of its proper divisors (1).

32113312132963 is an equidigital number, since it uses as much as digits as its factorization.

32113312132963 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 104976, while the sum is 40.

The spelling of 32113312132963 in words is "thirty-two trillion, one hundred thirteen billion, three hundred twelve million, one hundred thirty-two thousand, nine hundred sixty-three".