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321140313103201 is a prime number
BaseRepresentation
bin100100100000100110100111…
…0010010010001101101100001
31120010001201021120200200120221
41021001031032102101231201
5314043030330123300301
63055001453445403041
7124433423222122444
oct11101151622215541
91503051246620527
10321140313103201
11933639296aa669
1230027189109481
1310a2652b381327
1459433ba14d65b
15271d8e33c8da1
hex124134e491b61

321140313103201 has 2 divisors, whose sum is σ = 321140313103202. Its totient is φ = 321140313103200.

The previous prime is 321140313103171. The next prime is 321140313103271. The reversal of 321140313103201 is 102301313041123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 288353511950625 + 32786801152576 = 16980975^2 + 5725976^2 .

It is a cyclic number.

It is not a de Polignac number, because 321140313103201 - 245 = 285955941014369 is a prime.

It is a super-2 number, since 2×3211403131032012 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (321140313103271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160570156551600 + 160570156551601.

It is an arithmetic number, because the mean of its divisors is an integer number (160570156551601).

Almost surely, 2321140313103201 is an apocalyptic number.

It is an amenable number.

321140313103201 is a deficient number, since it is larger than the sum of its proper divisors (1).

321140313103201 is an equidigital number, since it uses as much as digits as its factorization.

321140313103201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 321140313103201 its reverse (102301313041123), we get a palindrome (423441626144324).

The spelling of 321140313103201 in words is "three hundred twenty-one trillion, one hundred forty billion, three hundred thirteen million, one hundred three thousand, two hundred one".