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32114131333033 is a prime number
BaseRepresentation
bin1110100110101001001110…
…11000111110111110101001
311012201002012000210001022211
413103110213120332332221
513202124220110124113
6152145010034445121
76523112053253401
oct723244730767651
9135632160701284
1032114131333033
11a261587a18672
123727b257337a1
1314bc471086379
147d049199d801
153aa567917b3d
hex1d352763efa9

32114131333033 has 2 divisors, whose sum is σ = 32114131333034. Its totient is φ = 32114131333032.

The previous prime is 32114131333027. The next prime is 32114131333073. The reversal of 32114131333033 is 33033313141123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24413905927849 + 7700225405184 = 4941043^2 + 2774928^2 .

It is a cyclic number.

It is not a de Polignac number, because 32114131333033 - 213 = 32114131324841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32114131332986 and 32114131333004.

It is not a weakly prime, because it can be changed into another prime (32114131333073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16057065666516 + 16057065666517.

It is an arithmetic number, because the mean of its divisors is an integer number (16057065666517).

Almost surely, 232114131333033 is an apocalyptic number.

It is an amenable number.

32114131333033 is a deficient number, since it is larger than the sum of its proper divisors (1).

32114131333033 is an equidigital number, since it uses as much as digits as its factorization.

32114131333033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 31.

Adding to 32114131333033 its reverse (33033313141123), we get a palindrome (65147444474156).

The spelling of 32114131333033 in words is "thirty-two trillion, one hundred fourteen billion, one hundred thirty-one million, three hundred thirty-three thousand, thirty-three".