Base | Representation |
---|---|
bin | 1001010110001011001… |
… | …00110100011100011011 |
3 | 1010200220221222100121120 |
4 | 10223011210310130123 |
5 | 20230144414442301 |
6 | 403310350540323 |
7 | 32126130610536 |
oct | 4530544643433 |
9 | 1120827870546 |
10 | 321142343451 |
11 | 114217531916 |
12 | 522a5b076a3 |
13 | 2438c0915c7 |
14 | 11787029a1d |
15 | 8548876e36 |
hex | 4ac593471b |
321142343451 has 4 divisors (see below), whose sum is σ = 428189791272. Its totient is φ = 214094895632.
The previous prime is 321142343449. The next prime is 321142343497. The reversal of 321142343451 is 154343241123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 321142343451 - 21 = 321142343449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (321142348451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53523723906 + ... + 53523723911.
It is an arithmetic number, because the mean of its divisors is an integer number (107047447818).
Almost surely, 2321142343451 is an apocalyptic number.
321142343451 is a deficient number, since it is larger than the sum of its proper divisors (107047447821).
321142343451 is a wasteful number, since it uses less digits than its factorization.
321142343451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107047447820.
The product of its digits is 34560, while the sum is 33.
Adding to 321142343451 its reverse (154343241123), we get a palindrome (475485584574).
The spelling of 321142343451 in words is "three hundred twenty-one billion, one hundred forty-two million, three hundred forty-three thousand, four hundred fifty-one".
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