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321203339950897 is a prime number
BaseRepresentation
bin100100100001000011111101…
…0111110100111101100110001
31120010021201222000211021210101
41021002013322332213230301
5314100043420011412042
63055050435521432401
7124441114124362135
oct11102077276475461
91503251860737711
10321203339950897
1193388631715148
123003743879b701
1310a2c463c32c51
1459464789d73c5
1527203817256b7
hex12421fafa7b31

321203339950897 has 2 divisors, whose sum is σ = 321203339950898. Its totient is φ = 321203339950896.

The previous prime is 321203339950859. The next prime is 321203339950943. The reversal of 321203339950897 is 798059933302123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 213526938978721 + 107676400972176 = 14612561^2 + 10376724^2 .

It is a cyclic number.

It is not a de Polignac number, because 321203339950897 - 219 = 321203339426609 is a prime.

It is a super-2 number, since 2×3212033399508972 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (321203339950817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160601669975448 + 160601669975449.

It is an arithmetic number, because the mean of its divisors is an integer number (160601669975449).

Almost surely, 2321203339950897 is an apocalyptic number.

It is an amenable number.

321203339950897 is a deficient number, since it is larger than the sum of its proper divisors (1).

321203339950897 is an equidigital number, since it uses as much as digits as its factorization.

321203339950897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 66134880, while the sum is 64.

The spelling of 321203339950897 in words is "three hundred twenty-one trillion, two hundred three billion, three hundred thirty-nine million, nine hundred fifty thousand, eight hundred ninety-seven".